Ŀ
                                                                       
           :             
                                                                       
             H=Hᠤ+h            ,                               
                                                                       
             Hᠤ-   ,(Hᠤ=1.28 )                         
             h -       ,(h=0.06 )         
                                                                       
             H = 1.28+0.06=1.34                                    
                                                                       
          :                        
                                                                       
             H=H+H      ,                                       
                                                                       
    H -         ,(H=0.4 )   
                                                                       
             H = 1.34+0.4=1.74                                        
                                                                       
                                      
                                                                       
      ---  
   ( %):                                                 
                                                                       
  CH4=53.6  C2H6=22.8  C3H8=6.1  C4H10=0.9  C5H12=0.2  CO2+H2S=0.2     
                                                                       
  N2=15.8  O2=0.4                                                      
                                                                       
      Q=40640 /.      
                                                                       
   pc=1.046 /.     
                                                                       
    1 :                                            
                                                                       
  V=0.0476*[2*CH4+3.5*C2H6+5*C3H8+6.5*C4H10+8*C5H12+1.5*H2S-O2]=      
  =0.0476*[2*53.6+3.5*22.8+5*6.1+6.5*0.9+8*0.2+1.5*0.1-0.4]=10.69 /
                                                                       
    ( )   :                 
                                                                       
  L=po*V=1.293*10.69=13.822 /                                    
                                                                       
        :                     
                                                                       
  VN2=0.79*V+N2/100=0.79*10.69+15.8/100=8.6 /                     
                                                                       
     ()    :               
                                                                       
  Vro2=0.01*[CO2+H2S+CH4+2*C2H6+3*C3H8+4*C4H10+5*C5H12]=1.22 /     
                                                                       
         :             
                                                                       
  VH2O=0.01*[H2S+2*CH4+3*C2H6+4*C3H8+5*C4H10+6*C5H12+0.124*a]+0.016*V
                                                                       
  a -    1    ,(a=10 /)        
                                                                       
  VH20=0.01*[0.1+2*53.6+3*22.8+4*6.1+5*0.9+6*0.2+0.124*10]+0.016*10.69=
  =2.23 /                                                          
                                                                       
      :                             
                                                                       
  V= Vr2+Vro2+VH2O=8.6+1.22+2.23=12.05 /                          
                                                                       
                                                                  Ĵ
                                                                  
                                                                  Ĵ
                                                                      

                                                                                                                                                                                                     
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